Find the remainder when fx 2×3 12×2 11x 2 is divided by x 5 7 3 3 7


What is the remainder when fx 2×3 12×2 11x 2 is divided by x 5 7 3 3 7?

We can use long division to find the answer to this question.

When we divide 2×3 by x, we get 6 with a remainder of 0.
When we divide 12×2 by x, we get 24 with a remainder of 0.
When we divide 11×2 by x, we get 22 with a remainder of 0.

Therefore, the answer is 0.

How to find the remainder when fx 2×3 12×2 11x 2 is divided by x 5 7 3 3 7?

To find the remainder when fx 2×3 12×2 11x 2 is divided by x 5 7 3 3 7, you first need to identify the dividend and the divisor. In this case, the dividend is fx 2×3 12×2 11x 2 and the divisor is x 5 7 3 3 7.

Next, you divide the dividend by the divisor to determine how many times the divisor goes into the dividend. In this case, we find that the divisor goes into the dividend five times.

Finally, we take the remainder of this division (5) and multiply it by the divisor (x 5 7 3 3 7). This gives us our answer: 5x 5 7 3 3 7.

The steps to finding the remainder when fx 2×3 12×2 11x 2 is divided by x 5 7 3 3 7

In order to find the remainder when fx 2×3 12×2 11x 2 is divided by x 5 7 3 3 7, you will need to follow these steps:

  1. First, factorize the equation by finding the greatest common divisor of all the terms.
  2. Next, divide each term by the greatest common divisor.
  3. Finally, multiply each term by the inverse of the greatest common divisor and simplify.

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