## The equation of a line is 6x+2y=18.

To find the x-intercept of the line, we need to set y = 0 and solve for x. This gives us:

6x + 2(0) = 18

6x = 18

x = 3

Thus, the x-intercept of the line is 3.

## The x-intercept of the line is the point where the line crosses the x-axis.

To find the x-intercept of the line, we need to set y = 0 and solve for x. We can do this by plugging y = 0 into the equation and solving for x.

6x + 2(0) = 18

6x = 18

x = 3

The x-intercept of the line is 3.

## To find the x-intercept of the line, we need to solve for x when y=0.

When y=0, the equation of the line becomes 6×2(0)+18=0.

We can then solve for x by using the Quadratic Formula:

x=-b±√b2-4ac2a

Since a=6, b=0, and c=18, we have:

x=-00±√002-4(6)(18)

x=-00±√3600

x=-00±60

Thus, the x-intercepts are 60 and -60.

## When y=0, the equation of the line becomes 6x=18.

To find the x-intercept of the line, set y=0 in the equation and solve for x. This gives us 6x=18. To solve this equation, we divide both sides by 6 to get x=3. This means that the x-intercept of the line is (3,0).

## To solve for x, we divide both sides of the equation by 6.

To solve for x, we divide both sides of the equation by 6.

On the left side of the equation, we have x2y18 divided by 6. This simplifies to x2y3.

On the right side of the equation, we have 18 divided by 6. This simplifies to 3.

Therefore, we have x2y3=3. We can solve for x by dividing both sides of this equation by y3. This gives us x2=1/y3 and therefore x=±1/√y3.

## This gives us x=3.

The equation of a line is 6x+2y=18. To find the x-intercept, we set y=0 and solve for x. This gives us x=3.

## Therefore, the x-intercept of the line is 3.

The x-intercept of the line is where the line crosses the x-axis. In this equation, the y-intercept is 0, so the line crosses the x-axis at 3.